Problem 57: Determine whether it is a subspace of the given vector space $\V$ $\V = \R^2$, and $S$ is the set of all vectors $(x, y)$ in $\V$ satisfying $3x + 2y = 0$. Solution: $S = \{x \in \R^2 : 3x+2y=0\}$. Let $(x_1,x_2),(y_1,y_2) \in S$. Then $3x_1+2x_2 = 0$ and $3y_1+2y_2 = 0$ Hence, $x + y = (x_1,x_2)+(y_1,y_2) =3x_1+2x_2 + 3y_1+2y_2 = 3(x_1+y_1) + 2(x_2+y_2)$ which implies that $(x_1+y_1,x_2+y_2) \in S$ Consequently, $S$ is closed under addition. Let $a \in \R$ and $(x_1,x_2) \in S$, then $ax = a(x_1,x_2) = a(3x_1+2x_2) = a0 = 0$ $=3(ax_1) + 2(ax_2) =0 $, which implies that $(ax_1,ax_2) \in S$ Therefore $S$ is also closed under scalar multiplication. It follows that $S$ is a subspace of $\R^2$.
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